7m^2+15m+8=0

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Solution for 7m^2+15m+8=0 equation: 



7m^2+15m+8=0

a = 7; b = 15; c = +8;
Δ = b2-4ac
Δ = 152-4·7·8
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-1}{2*7}=\frac{-16}{14}
=-1+1/7
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+1}{2*7}=\frac{-14}{14}
=-1
$

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